discussion question and peer reviews

ng>DISCUSSION POST MUST BE 10+ SENTENCES AND THE PEER REVIEWS MUST BE 7+ SENTENCES PLEASE USE YOUR OWN WORDS AND DO NOT COPY FROM OTHER SITES STAY ON TOPIC ,BE POSITIVE , AND DO NOT COMMENT ON GRAMMAR ERRORS. TALK DIRECTLY TO CLASSMATES IN PEER REVIEWS!!! YOU MUST COMPLETE BOTH PEER REVIEWS AND DISCUSSION QUESTION!! THANK YOU.

1) DISCUSSION QUESTION

Employees from Company A and Company B both receive annual bonuses. What information would you need to test the claim that the difference in annual bonuses is greater than $100 at the 0.05 level of significance? Write out the hypothesis and explain the testing procedure.

2) PEER REVIEW #1 (TAMMY)

Employees from Company A and Company B both receive annual bonuses. What information would you need to test the claim that the difference in annual bonuses is greater than $100 at the 0.05 level of significance? Write out the hypothesis and explain the testing procedure.

Explanation:

First, a sample of employees in each company, with their bonuses

nA ,nB

second, compute the average and standard deviation of the bonds in each company

third, hypothesis

H0:?A??B=100

H1:?A??B>100

fourth, value of the test statistic

ttest=spn11+n21(x1??x2?)?(?1??2)

fifth, value of p

P=P(t>ttest )

sixth, if p is less than 0.05, H0 is rejected….

From my understanding of hypothesis and what I recently learned from this course is that I know it is an educated guess. But in this scenario, the average between the two companies must be found weather the testing of the hypothesis is rejected or not. I feel that there could have been more information provided for this question but overall, the null hypothesis will be rejected if the maximum percent is 0.05. Also, if the p-value is less than then a two tailed test must be conducted and the null hypothesis should be rejected.

I really don’t know quite if I’m on the right track in regards to this discussion but I need feedback please.

3)PEER REVIEW #2 (MONICA

For this problem we have two independent variable, company A and company B, each having a bonus Mu 1 and Mu 2.  The claim is the difference between these variables is greater than $100. Mu 1 – Mu 2 > 100.  This is the alternative hypothesis. The opposite is the null hypothesis Mu 1 – Mu 2 <= 100.  From here we must determine which test statistic to use t or z. The t test is used because we don’t have a large enough sample size and standard deviation is unknown.Then calculate the p value. If the p value is less than 0.05 we will reject the null hypothesis. If it’s greater then we fail to reject it.

I am not sure how to notate the equation using my keyboard so I hope this explanation will suffice.